find the domain and range of the function :

Question

anonymous · Answer

$$y= 1-\sqrt{x}$$

anonymous · Answer

what would be the range? just y?

anonymous · Answer

domain? $$y-\sqrt{x}$$

anonymous · Answer

help

jtvatsim · Answer

any time you have a domain question look for two things:
1. Do you have any fractions? then don't let the denominator be 0.
2. Do you have any square roots? then don't let the inside be less than 0.

anonymous · Answer

dont be fooled by the funny name, jtvatsim is right

anonymous · Answer

the domain is $$0 \ge x ?$$

jtvatsim · Answer

almost other way around 0<= x

anonymous · Answer

ohhh, duh. lol thanks. but for my range(output) how would i get that?

anonymous · Answer

domain: {x element R : x>=0}  (all non-negative real numbers)
range: {y element R : y<=1}

jtvatsim · Answer

we plug in extreme values from our domain.
The smallest x will ever be is 0. so y = 1-sqrt(0) = 1
The biggest x will ever be is infinity so y = 1 - sqrt(infinity) = 1 - infinity = -infinity.
Or like kitt020912 said y<=1

jtvatsim · Answer

In other words y can be anything between 1 and -infinity.

anonymous · Answer

ahhh, i see... let me about this a little bit:)

jtvatsim · Answer

k , good luck! :)

anonymous · Answer

thanks, you guys rock!

anonymous · Answer

OH MAN, i wanted to give multiple medals. sorry jvatsim. you're an ace in my book too:)