I have the answer can someone just see if I am correct?
Rewrite the following function in the form
f(x)=kx^p.
f(x)=((2x^2)/(4x^4))
k=
p=

Question

I have the answer can someone just see if I am correct?
Rewrite the following function in the form 
f(x)=kx^p.
f(x)=((2x^2)/(4x^4))
k=
p=

anonymous · Answer

Could you please tell me your answers?

anonymous · Answer

k=-2 and p=-2

anonymous · Answer

Nope, that's incorrect. You got p correct, but k is incorrect.

anonymous · Answer

Is k=-8

anonymous · Answer

$$f(x)=\frac{2x^2}{4x^4}$$
$$=\frac{x^2}{2x^4}$$
$$=\frac{1}{2x^2}$$
$$=\frac{1}{2}\times \frac{1}{x^2}$$
$$=\frac{1}{2}\times x^{-2}$$
$$=\frac{1}{2}x^{-2}$$

anonymous · Answer

Nope. Way off. Never just pull out a rabbit out of the hat and give me a random number.

anonymous · Answer

so then k=.5 and p=-2 sorry I typed in the to the calculator the wrong thing a dn just took the answer without looking at it first soorry and thank you

anonymous · Answer

No worries. And best you do these types without a calculator. That's something you should ponder about doing instead of using the calcualtor, because most calculators can't put x's and y's.