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OpenStudy (anonymous):
I have the answer can someone just see if I am correct?
Rewrite the following function in the form
f(x)=kx^p.
f(x)=(2x)(5square root x)
k=
p=
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OpenStudy (anonymous):
\[f(x)=(2x)(5\sqrt{x})\]
OpenStudy (jtvatsim):
what do you have?
OpenStudy (anonymous):
k=10 and p= 2
OpenStudy (jtvatsim):
k is good, how did you get p?
OpenStudy (anonymous):
well that is were I'm not sure if I did it right what do you do with the square root
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OpenStudy (jtvatsim):
ok, the trick is \[\sqrt{x}=x^{\frac{1}{2}}\]
OpenStudy (anonymous):
oh so if there are no numbers always =.5
OpenStudy (anonymous):
so then k=10 and p=.5 correct
OpenStudy (jtvatsim):
close, you have one x with nothing so that is x^1 and another x with x^(1/2) so you get x^(1 + 1/2) = x^(3/2)
OpenStudy (anonymous):
k= 10 and then p=1.5 right
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OpenStudy (jtvatsim):
to clarify what you said earlier if there are no numbers AND there is a square root than it is .5 :)
OpenStudy (jtvatsim):
correct!
OpenStudy (anonymous):
ok thank you
OpenStudy (jtvatsim):
the general formula is this:
\[\sqrt[a]{x^b}=x^{\frac{b}{a}}\]
OpenStudy (anonymous):
ok
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OpenStudy (jtvatsim):
no problem!
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