G.I. Amatree drew a circle with center O with BC = 2AC. After doing some measuring he calculated the area of ΔABD to be 48 cm². Based on his calculations what would be the area of ΔDCO be?
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Let BC=x Then AC=2x
CO would be equal to x. since DC bisects AO
But BC is longer than CO...
CO cannot be equal to x since BC is equal to x.
Oh oops make AC=x
I got them mixed up. Sorry mate.
I think I can handle OC, but how can I find DC?
So BC=2x
Wait, 2DC = AB · BC, right?
or DC²?
I think I got it. You use similar triangle proof.
Tell me what BO is first.
I think the angle ADO is bisected. SO then ACD is similar to DCO.
BO=OD, because of equal radii.
Then you use corresponding sides in similar triangles to find x first.
Once you do that, you're about 10m to the finish line. ALl you got to do is use pythagoras to find your DC
And then you can find the area after that.
Hmm, it may work.
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