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Mathematics 17 Online
geerky42 (geerky42):

G.I. Amatree drew a circle with center O with BC = 2AC. After doing some measuring he calculated the area of ΔABD to be 48 cm². Based on his calculations what would be the area of ΔDCO be?

geerky42 (geerky42):

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OpenStudy (anonymous):

Let BC=x Then AC=2x

OpenStudy (anonymous):

CO would be equal to x. since DC bisects AO

geerky42 (geerky42):

But BC is longer than CO...

geerky42 (geerky42):

CO cannot be equal to x since BC is equal to x.

OpenStudy (anonymous):

Oh oops make AC=x

OpenStudy (anonymous):

I got them mixed up. Sorry mate.

geerky42 (geerky42):

I think I can handle OC, but how can I find DC?

OpenStudy (anonymous):

So BC=2x

geerky42 (geerky42):

Wait, 2DC = AB · BC, right?

geerky42 (geerky42):

or DC²?

OpenStudy (anonymous):

I think I got it. You use similar triangle proof.

OpenStudy (anonymous):

Tell me what BO is first.

OpenStudy (anonymous):

I think the angle ADO is bisected. SO then ACD is similar to DCO.

OpenStudy (anonymous):

BO=OD, because of equal radii.

OpenStudy (anonymous):

Then you use corresponding sides in similar triangles to find x first.

OpenStudy (anonymous):

Once you do that, you're about 10m to the finish line. ALl you got to do is use pythagoras to find your DC

OpenStudy (anonymous):

And then you can find the area after that.

geerky42 (geerky42):

Hmm, it may work.

OpenStudy (anonymous):

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