Select all the asymptotes of f(x)=((x-7)/(x^2-2x-8))
asymptotes possibly occur when the denominator equals 0. Try setting the denominator equal to 0 and solving for x to find where the asymptotes are.
solve that separately from the original question. :)
set the denominator to equal 0. Factor the polynomial and that way you'll get the values that will make the denominator 0. Since no denominator can be 0 (because it'll be an error), the values you get will be the asymptote of your function. Here's a hint your factors would be: (x+2)(x-4)=0
ok so then are my asymptote just x=2 and x=-4
oh no they are x=-2 and x=4 right the signs switch
yep!
so then those are my asymptote
yup! another way of making sure you have them right is to use a graphing calculator...
Oh ok do I have to do anything with the x-7 on top or that doesn't have anything to do with the asymptote?
nope, it does not have to do anything with the vertical asymptotes ;)
ok thanks
no problem!
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