mass of 9.93*10^24 mols of CH3OH

Question

abb0t · Answer

Use dimensional analysis.

Find the sum of methanol (CH3OH).
carbon + 4(hydrogen) + oxygen = total mass (g/ mol)

then cross cancel out units to get mass.

abb0t · Answer

$$mol \times \frac{ gram }{ mol }$$

aaronq · Answer

for the information you provided, the process abb0t described is correct. But that amount of moles seems very unlikely, it would give you ~3*10^23 Kg.. which is a lot, but still possible in an industrial setting... are you sure it doesn't read "9.93*10^24 molecules"?

abb0t · Answer

I usually don't think of other factors. I assume this is for H.S. chemistry. Otherwise, I would of said the same thing. And I think all they are looking for is that they amster the concept of cross canceling.

unklerhaukus · Answer

that $is$ a lot of ethanol

aaronq · Answer

yeah, thats true, they are probably just working on conversions.