Question

what are the foci of the hyperbola given by the equation (x+10)^2/25-(y+1)^2/9=1

Answer 1

\[\frac{ (x+10)^2 }{ 25 }- \frac{ (y+1)^2 }{ 9 }=1\]
Standard form of a horizontal hyperbola is:\[\frac{ (x-h)^2 }{ a^2 }- \frac{ (y-k)^2 }{b^2 }=1\]with foci \[(h \pm c, k)\]
where c is...\[c^2 = a^2 +b^2\]

Answer 2

So would it be -10 plus or mince sqrt(34,-1

Answer 3

@agent0smith

Answer 4

That... looks correct!

Answer 5

thank you so much!

Answer 6

You're welcome :)