An object is supplied with 6000 J of heat energy and its temperature increases from 15 C to 18 C. Calculate the thermal capacity of the object

Question

anonymous · Answer

what do you understand by the word thermal capacity?

anonymous · Answer

He means specific heat capacity which is the amount of energy required to raise the temperature of the object a degree. In the is case the objects temperature went up 3 degrees and 6000 joules of energy were supplied so 6000/3 = 2000 Joules/Kelvin

anonymous · Answer

yea well i was trying to get him to answer the question  :P

anonymous · Answer

I apologize, I thought you were confused by the question

anonymous · Answer

nah.. :P.. i always try not to give direct answer.. but just try to understand what is it that you don't get.. and only help you to get the solution yourself ;-)

anonymous · Answer

and besides. there is a difference between specific heat and thermal capacity... :P..

anonymous · Answer

I understand the thermal capacity and Specific heat capacity and I know the equation linking them which is: 
$$Energy= Mass \times Specific Heat Capacity \times Diffrence \in Tempera$$

anonymous · Answer

so what is it that you don't get?