Question

need help solving and graphing following functions:
1. y=(-3/4)x + 5
2.y= x^2-4
3. y= -3x^2 -6x -5

Answer 1

i know the first one is a line and other 2 are parboles

Answer 2

yes, you can use a table coordinate system for number 1

Answer 3

just substitute x = 0,1,2,3,4, and you get your line, easy.

Answer 4

for 1 i have y interept of 5

Answer 5

second one, it's a perfect square
x^2 - 4 = (x-2)(x+2)

Answer 6

and xintercept of 6 2/3

Answer 7

the second one is a parbole correct

Answer 8

so i need ot find the vertex first

Answer 9

Yep. so you can graph it now, since (x-2)(x+2)= y. just plot in points
x = 0,1,2,3,4

Answer 10

and once you see the graph, you'll get the vertex. Visually seeing it first can make it easier.

Answer 11

i rather use the formula

Answer 12

do you have the formula?

Answer 13

i think this is it -b/2(a) right

Answer 14

yes

Answer 15

-b/2a, then use this number and plug it in the original f(x) to get the y coordinate

Answer 16

amoondarya ty can u show me how u solved it

Answer 17

they r three seperate problems

Answer 18

dpalnc any ideas

Answer 19

y= (-3/4)x +5 to have a y intercept put 0 in for x and get 5 so y intercept is (0,5)

Answer 20

the xintercept would be 0 for y and you get 6 2/3 so it would be (6 2/3 , 0) for x intercept

Answer 21

then a thrid point could be 4 for x then get y= (-3/4)4 + 5 so it would be y=-3 + 5
so y=2 so thrid point is (4,2)