find the derivative of e^(2x) using the product rule
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OpenStudy (anonymous):
\[(f \prime) e ^{2x}\]
OpenStudy (anonymous):
I know its 2e^(2x), but i'm not sure why. I know e^x is equal to its derivative but thats about it
OpenStudy (anonymous):
the derivative of \[e^{f(x)}\]
is
\[e^{f(x)}*f'(x)\]
OpenStudy (anonymous):
Do you know the derivative for \[f(x)=2x\]
OpenStudy (anonymous):
its 2
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OpenStudy (anonymous):
Correct
OpenStudy (anonymous):
And that makes sense I just didn't know the rule that you just used. Should be handy. Is it only good for e?
OpenStudy (anonymous):
yes
OpenStudy (anonymous):
Awesome thanks. Good to remember. I haven't explicitly been taught that, but i guess i was just suposed to figure it out since it said to use the product rule,which i have learned
OpenStudy (anonymous):
oh duh i just figured out another way to look it as e^2x = e^x * e^x
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OpenStudy (anonymous):
The problem is that mj632 is using the chainrule but the question strickly says the use of the product rule.
Here e\[e ^{2x}=e ^{x}*e ^{x}\] and aplying the product rule you'll get
\[e ^{x}e ^{x}+e ^{x}e ^{x}=e ^{2x}+e ^{2x}=2e ^{2x}\]
OpenStudy (anonymous):
awesome. thanks!
OpenStudy (anonymous):
nice you figured it out yourself already:)
OpenStudy (anonymous):
ha, that tends to happen. thanks though. Still gave ya a medal
OpenStudy (anonymous):
haha no probs and thanks^^
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