Question

I have an answer can someone just see if I'm right
Rewrite the following function in the form
f(x)=kx^p
f(x)=(1/2x^3)
k=
p=

Answer 1

k=.5 and p=-3

Answer 2

hi

Answer 3

hi

Answer 4

\[f(x)=kx^p\]
\[p = -3\]
\[k = 0.5\]

Answer 5

so i am correct thanks

Answer 6

yep :)

Answer 7

Did you have anymore questions?

Answer 8

yes actually f(x)=3 square root x and then the 4 foes inside the check mark on the square root
k=
p=

Answer 9

\[f(x)=3\sqrt[4]{x?}\]

Answer 10

Ah yes, do you know what
\[\sqrt[4]{x}\]
is equivalent to?

Answer 11

no

Answer 12

\[\sqrt{x} = x^{\frac{1}{2}}\]

Answer 13

ok

Answer 14

What would \[\sqrt[4]{x}\] be?

Answer 15

so then does k= 3 and p= .25

Answer 16

12.649

Answer 17

Correct

Answer 18

so k=3 and p=.25 right just making sure of the numbers

Answer 19

yes, that's correct

Answer 20

ok I have another so you want to check my answers for that too

Answer 21

f(x)=(2/square root of x
k=
p=

Answer 22

okay \[f(x)=\frac{2}{\sqrt{x}}\]

Answer 23

yes k= 2 and p=1

Answer 24

Do you know what happens when you bring the numerator to the denominator?

Answer 25

no

Answer 26

\[\sqrt{x}=x^{\frac{1}{2}}=\frac{1}{x^{-\frac{1}{2}}}\]

Answer 27

so then k=2.5 and p=0

Answer 28

no

Answer 29

k=2 and p=-0.5

Answer 30

\[f(x)=\frac{2}{\sqrt{x}}=2*x^{-\frac{1}{2}}\]

Answer 31

Correct

Answer 32

ok thanks what about f(x)=(2x)(5 square eoot of x)

Answer 33

k=10 and p=-1.5

Answer 34

This?
\[(2x)\sqrt[5]{x}\]

Answer 35

no the 5 is next to the square root not in it

Answer 36

ah

Answer 37

\[(2x)(5)\sqrt{x}\]

Answer 38

\[(2x)(5\sqrt{x}\]

Answer 39

This one is easy, we've already done something similar before

Answer 40

k=10 and p=-1.5

Answer 41

is that right

Answer 42

\[2x(5*\sqrt{x})\] is equivalent to
\[2x(5^1*x^{\frac{1}{2}})\]

Answer 43

so then k=10 and p=1.5

Answer 44

sorr yp=.5

Answer 45

yes
k=10 p=.5

Answer 46

ok thanks

Answer 47

No problem.