help to solve please. 51x=2x^2+72
\[2x^2-51x+72=0\] I believe you have to use the quadratic equation again. \[x=-b \pm \sqrt{b^2-4ac}/2a \] \[ax^2+bx+c\] so a=2 b=-51 c=72
I got x=24 or 1.5
do you mind walking through it with me?
yep, x=3/2 x=24
\[-(-51)+\sqrt{(-51^2-4(2)(72)}/2(2)\]
\[-(-51)-\sqrt{(-51^2-4(2)(72)}/2(2)\]
Those are the equation you get when you plug a,b, and c into the quadratic equation.
You have two equations because the quadratic equation has the opposite of b plus or minus the square root b squared minus four ac all divided by 2a.
The first equation should give you a value of 24 and the second equation should give you a value of 1.5
You can always check your answers as well by plugging them into the original equation. For instance \[2(24^2)-51(24)+72=0\]
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