Question

sec theta/sin theta - sin theta/cos theta

I've gotten it down to 1-sin ^2 theta/ sin theta

Answer 1

\[1-\sin ^{2}\theta/\sin \theta\]

Answer 2

1-sin^x = cos^x, remember?

Answer 3

Don't forget that \[\cot x =\frac{ \cos x}{\sin x} = \frac{1}{\tan x}\]

Answer 4

\[
\frac{\sec(\theta)}{\sin(\theta)} - \frac{\sin(\theta)}{\cos(\theta)} \equiv
\frac{1}{\sin(\theta)\cos(\theta)} - \frac{\sin(\theta)}{\cos(\theta)} \equiv
\frac{1 - \sin^2(\theta)}{\sin(\theta)\cos(\theta)} \equiv
\frac{\cos^2(\theta)}{\sin(\theta)\cos(\theta)} \\

\frac{\cos^2(\theta)}{\sin(\theta)\cos(\theta)} \equiv
\frac{\cos(\theta)}{\sin(\theta)} \equiv
\cot(\theta)
\]

Answer 5

I swear I stare straight at these things. i'm so sorry mr. palmer. :(

Answer 6

or miss...idk o.o

Answer 7

my friends call me Bill

Answer 8

Natalie :) pleasure to meet you Bill.

Answer 9

OKAY go rescue someone else, i'll go to the next one!