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how do I solve sqrt8^3+sqrt2x
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\[\sqrt{8^{3}}+\sqrt{2x}\]?
That's not an equation, so it cannot be solved. It can be simplified however. Is that what you need?
haha my bad yes
Ok. First, what is 8^3?
22.62
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That is not 8^3. That is 8^(3/2) truncated at two decimal places. Again, what is 8^3?
2
*Sigh.* \[8^{3}=8\times8\times8\]What is that equal to?
512
Right. Now\[\sqrt{512}=\sqrt{2\times 256}=\sqrt{2}\times\sqrt{256}\]What is\[\sqrt{256}\]?
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16
Right. So\[\sqrt{8^{3}}+\sqrt{2x}=16\sqrt{2}+x^{\frac{1}{2}}\sqrt{2}=(16+x^{\frac{1}{2}})\sqrt{2}\]
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