Question

could someone just give me the steps for solving this prob? Solve the equation by using factoring: x2 -14x + 49 =0

Answer 1

start by looking at the factors of 49

Answer 2

7*7

Answer 3

break the mid term
x^2-7x-7x+49
now factor the first two terms and last two terms .

Answer 4

Factorise the quadratic so that you get something of the form \((x\pm a)(x\pm b)\).
With a quadratic of the form \(ax^2+bx+c\), you generally should look to find products of \(c\) that sum to \(b\).

Answer 5

i havent learned quads yet

Answer 6

so x^2-7x=0 -7x+49=0 and i try to solve for x in each one?

Answer 7

no
x^2-7x-7x+49=0
x*(x-7)-7(x-7)=0
(x-7)(x-7)=0

Answer 8

um these are my answers
14
7
2
no solution

Answer 9

the answer is 7?

Answer 10

Factorising is effectively finding the roots, the same as using the quadratic formula (although factorising isn't always possible if the roots aren't integer).

A quadratic is any equation of the form \(ax^2+bx+c\) - in your case, a = 1, b = -14 and c = 49.

Find the products of \(c\): [1,49], [-1,-49], [7,7], [-7,-7]
From the products, find which pair sum to \(b\): -7 + -7 = -14.

Then you have the factorised form: \((x-7)(x-7)\). So you know the roots will be 7, as this will result in at least one (in this case, both) terms equating to zero.

Answer 11

yes its 7

Answer 12

myhomework says to find it by factoring

Answer 13

thanks guys

Answer 14

I've just told you how to factor it.