Question

i dont know how to solve this=p
81x^2-49=0

the next step is 81x2-49=0

right? what do i do next?

Answer 1

add \(49\) to both sides, you will get
\[81x^{2}=49\]
then take the square root of both sides,
\[\pm9x=\pm7\]
then divide by \(\pm9\) on both sides,
\[x=\pm\frac{7}{9}\]

Answer 2

i havent learned that yet..

Answer 3

which part? I'll explain to you slower.

Answer 4

anyone else?

Answer 5

\[81x^{2}-49+49=0+49\] do you get this part?

Answer 6

yes

Answer 7

\[\sqrt{81x^2}=\sqrt{49}\] do you get this part?

Answer 8

not really whya re you doing that?

Answer 9

because the square root of the left hand side will always equal to the square root of the right hand side.
for example.
\[\sqrt{9}=\sqrt{3*3}\]or\[\sqrt{4}=\sqrt{\frac{8}{2}}\]

Answer 10

do you understand this part? i will explain in detail if you dont :)