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\[\lim_{x \rightarrow 1} \frac{ x^4+x^3-2x }{ x^5+2x-3 }\]
caluclateing limits using limit laws. my answer is \[\lim_{x \rightarrow 1}\frac{ x(x^3+x^2-2) }{ x(x^4;2-3x^-1) }\]
and cacel out x?
won't do you any good.
what is the first step in order to solve this?
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at x=1 it is 0/0 so (if you know it) you can use L'Hospital's rule take the derivative to top and bottom, then let x-> 1
i know that i have to factorize.
so i dont need to factorize?
I apologize I cannot do this one at the moment.
ok, thanks for letting me know
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sure thing, good luck.
you can factor out (x-1) because you see x=1 makes the polynomial zero, so 1 is a root.
then cancel the (x-1) factor from top and bottom, and evaluate the resulting expression at x->1
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