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OpenStudy (anonymous):
\[\lim_{x \rightarrow 1} \frac{ x^4+x^3-2x }{ }\]
OpenStudy (anonymous):
not working so
Lim x^4+x^3-2x/x^5+2x-3
x->1
OpenStudy (zehanz):
Do you mean l'Hôpital's Rule by limit law?
In that case take the derivative of both the numerator and the denominator and then take the limit as x goes to 1.
OpenStudy (anonymous):
yes!
OpenStudy (anonymous):
I thought I need to factorize first
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OpenStudy (zehanz):
That can help sometimes, but factorising the denominator is difficult and l'H will crack it anyway...
OpenStudy (anonymous):
Whats I`H?
OpenStudy (anonymous):
I have to go meeting but I will back later. thanks,
OpenStudy (zehanz):
l'H = l'Hôpital's Rule
OpenStudy (anonymous):
Do i plug numbers into the equation>?
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OpenStudy (anonymous):
No, using l'Hôpital's Rule allows you to take the limit as x goes to 1 of the top and bottom separately.
OpenStudy (zehanz):
So, after differentiating separately yo now have this:\[\lim_{x \rightarrow 1}\frac{ 4x^3+3x^2-2 }{ 5x^4+2 }\]No 0/0 problem anymore, just set x=1 to see the result.