Solve: (1/10)^y=100^(y+3)
\[(\frac{1}{10})^y = 100^{(y+3)}\] Some useful properties of exponents: \[(\frac{a}{b})^n = \frac{a^n}{b^n}\] \[a^{-n} = \frac{1}{a^n}\]
and \[(ab)^n = a^nb^n\]
just what I was about to add :)
So, I would turn the expression on the left into something more like the expression on the right via the 2nd property
\[1^{y}/10y \] = .... how do you solve\[100 ^{y+3}\] with maybe laws of exponents? I'm not sure
****[10^{y}\]
please help:)
Can't you write \[100^{y+3} = 10^{y+3}10^{y+3}\]?
like \[(10^{2})^{y+3}\]?
\[10^{-y}=100^{y+3}=10^{10y+30}\] thus \[-y= 10y+30\]
heheh i mean -y=2y+6
Okay, here's how I would do it: \[y^{-1} = 100^{y+3}\]split rhs \[y^{-1}=10^{y+3}10^{y+3}\]Multiply both sides by \(10^y\) \[1= 10^0 =10^y10^{y+3}10^{y+3}\]Log base 10 of both sides \[0= y+y+3+y+3\]\[y=-2\]
sorry, miswrote the left hand side in the first two lines, should have been \(10^{-y}\)
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