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OpenStudy (anonymous):
Solve:
(1/10)^y=100^(y+3)
13 years ago
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OpenStudy (whpalmer4):
\[(\frac{1}{10})^y = 100^{(y+3)}\]
Some useful properties of exponents:
\[(\frac{a}{b})^n = \frac{a^n}{b^n}\]
\[a^{-n} = \frac{1}{a^n}\]
13 years ago
OpenStudy (whpalmer4):
and \[(ab)^n = a^nb^n\]
13 years ago
OpenStudy (anonymous):
just what I was about to add :)
13 years ago
OpenStudy (whpalmer4):
So, I would turn the expression on the left into something more like the expression on the right via the 2nd property
13 years ago
OpenStudy (anonymous):
\[1^{y}/10y \] = ....
how do you solve\[100 ^{y+3}\]
with maybe laws of exponents? I'm not sure
13 years ago
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OpenStudy (anonymous):
****[10^{y}\]
13 years ago
OpenStudy (anonymous):
please help:)
13 years ago
OpenStudy (whpalmer4):
Can't you write \[100^{y+3} = 10^{y+3}10^{y+3}\]?
13 years ago
OpenStudy (anonymous):
like \[(10^{2})^{y+3}\]?
13 years ago
OpenStudy (anonymous):
\[10^{-y}=100^{y+3}=10^{10y+30}\]
thus
\[-y= 10y+30\]
13 years ago
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OpenStudy (anonymous):
heheh i mean -y=2y+6
13 years ago
OpenStudy (whpalmer4):
Okay, here's how I would do it:
\[y^{-1} = 100^{y+3}\]split rhs
\[y^{-1}=10^{y+3}10^{y+3}\]Multiply both sides by \(10^y\)
\[1= 10^0 =10^y10^{y+3}10^{y+3}\]Log base 10 of both sides
\[0= y+y+3+y+3\]\[y=-2\]
13 years ago
OpenStudy (whpalmer4):
sorry, miswrote the left hand side in the first two lines, should have been \(10^{-y}\)
13 years ago
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