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Which sum or difference identity would you use to verify that cos (180° - q) = -cos q?
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How about \[\cos(a-b) = \cos a \cos b + \sin a \sin b\] with a = 180 degrees?
It's not even worth trying to explain it cx Just tell me? cx
Opps didn't realize that was the answer >_<
I just looked down a list of sum and difference identities until I saw one that had cos (a-b)...what's there to explain? :-)
>_< wow I'm dumb, and idk
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What you might need is a handy trig reference sheet. Here's one: http://tutorial.math.lamar.edu/pdf/Trig_Cheat_Sheet.pdf
thanks c:
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