How do you find the slope-intercept form of 7x-3y=-12.

Question

anonymous · Answer

Standard form:
$$Ax + By = C$$Slope-Intercept form:
$$y = mx + b$$ 
Basically, all you need to do is solve for y. 
$$ 7x-3y=-12 $$Subtract 7x from both sides.$$-3y= -7x -12$$Divide both sides by -3.
****-7 divided by -3 would be -7/-3, but since both the numerator and denominator are negatives, we switch the fraction to a positive.
Final result.$$y = 7/3 + 4$$

anonymous · Answer

@Josh45680

anonymous · Answer

How do you subtract from both sides? Why is 12 still there?

anonymous · Answer

Ok lets go through this step by step.

7x - 3y = -12

To get that into Slope-Intercept form, we need to isolate 'y'.

We want to eliminate 7x from the left side of the equation. Since its a positive (7x), we subtract 7x from both sides:

7x - 7x - 3y = -12 - 7x

So your left with -3y = -12 - 7x. You get it so far?

anonymous · Answer

Umm.. Sure. Thanks for your help