Want to make sure I've got the right idea with this problem (in comments)...
If an object travels one half of its total path in the last second of its fall from rest. How high was it initially? \[x(t) = \frac{ 1 }{ 2 } g t^2\]\[x(t-1)=\frac{ 1 }{ 4 }[-g (t-1)^2]\]\[\frac{ -g t^2 }{ 2 }-\frac{ -g (t-1)^2 }{ 2 }=\frac{ -g t^2 }{ 4 }\] \[-\frac{ 1 }{ 2 }g(-2t+1)=-\frac{ g t^2 }{ 4 }\]\[\frac{ 1 }{ 4 }t^2-t+\frac{ 1 }{ 2 } = 0\]\[t^2-4t+2=0\]\[\frac{ 4\pm \sqrt{16-8} }{ 2 }\]\[t=3.41s, 0.5858s\]And the 0.5858s gets discarded because t>1. When I plug that in to the original x equation, I get\[-\frac{ 1 }{ 2 }(-9.81m/s^2)(3.41s)^2\]\[=57.036 m\] I looked this up to check my answer, and the number I saw was 48.something... I absolutely could not figure out how they got that number. Basically I just want to check my work... it's for an exam review and I'm stressing!
Use the supposed answer to see if it is correct.
It worked ^_^; I should have thought of that.
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