An investor invested a total of 2,100 in two mutual funds. One fund earned a 8%profit while the other earned a 5% profit. if the investors total profit was 129 how muchwas invested in the mutual fund? The amount investead in the mutual fund earned 8% was= ? The amount investead in the mutual fund earned 5% was=?
@agent0smith can you please help me?
Let x be the amount invested in the 8% fund. (2100-x) will be invested in the 5% fund. x*8% is the return on the 8% fund. (2100-x)*5% is the return on the 5% fund. The sum of the two returns is 129. Converting the percentages to decimals, we have \[x*0.08 + (2100-x)*0.05 = 129\] Solve that for \(x\) to find the amount invested in the fund that earned 8%. Subtract \(x\) from 2100 to find the amount in the fund that earned 5%. You might multiply both sides of the equation by 100 as a first step to get rid of the decimals.
would x=2,075.8 @whpalmer4
\[8x + 5(2100-x) = 12900\] \[8x -5x + 10500 = 12900\] \[3x = 2400\] x=?
x=800 @whpalmer4 were did you get 12900 from
nvm i saw my mistake i forgot to multiply 100 to 129 @whpalmer4
when I multiplied both sides by 100
How much is invested in the 5% fund?
is that the 8% answer? @whpalmer4
"Let x be the amount invested in the 8% fund. (2100-x) will be invested in the 5% fund."
1,300 @whpalmer4
Okay, 800 @ 8%, 1300 @ 5%
Thank you so much! those are the answers right? @whpalmer4
800 * 8% = 64 1300 * 5% = 65 64 + 65 = 129 Looks like they are correct.
thank you so so so much! @whpalmer4 time for the next question hehe
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