Ask your own question, for FREE!
Mathematics 10 Online
OpenStudy (anonymous):

Question on similarity.

OpenStudy (anonymous):

OpenStudy (anonymous):

Explanation on how to work this out would be greatly appreciated.

OpenStudy (anonymous):

pic

OpenStudy (anonymous):

I would like more of a explanation, not just answer...

OpenStudy (anonymous):

if the steps arent enough, cant help

OpenStudy (anonymous):

Thanks for trying, I appreciate it.

OpenStudy (anonymous):

@hartnn Do you think you know how to work this out?

OpenStudy (anonymous):

luis_rivera explains it very well. first break up the two fractions. you have (x+3)/3 = (y+2)/2 to start with break up the fractions x/3 + 3/3 = y/2 + 2/2 // simplify the 3/3 and 2/2 since they both equal 1 x/3 + 1 = y/2 + 1 // subtract 1 from both sides. x/3 = y/2 // the above equation is the answer you are looking for.

OpenStudy (anonymous):

How do the fractions break up like that?

OpenStudy (anonymous):

ok, suppose you have 2/3 + 3/3 what is that well, (2+3)/3 just do that backwards for (x+3)/3. the x is like the 2 in my example x/3 + 3/3

OpenStudy (anonymous):

Oh okay I see! Thanks for helping out!

OpenStudy (anonymous):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!