Question

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A circular clock face has a diameter of 7 inches. What is the area of the clock face? Round to the nearest tenth.
A)38.5 in.2
B)11 in.2
C)49 in.2
D)153.9 in.2

Answer 1

i need the answer i have to turn it in in 5min

Answer 2

For the second one, pythagoras theorem
\[21^2 = 8^2 + x^2\]rearrange to find x...\[21^2 -8^2 = x^2\]
\[\sqrt {21^2 -8^2} = x\]

Answer 3

i am sorry bu ti dont get it i am a 4th grader

Answer 4

dont*

Answer 5

help plzz

Answer 6

\[A=\pi*r^2\]
R is the radius, which is half of the diameter. So, divide the diameter of 7 by 2, which is 3.5:
\[A=\pi*3.5^2\]\[A=\pi*12.25\]
The pi symbol has a value of 3.14, so multiply 3.14 by 12.25:
\[A=38.465\]When rounding, looking at the place value after the number, if the number is 5 or greater, than you round the number up. In this case, 6 after the 4 is greater than 5, therefore the 4 will turn into a 5:
\[A=38.5\]

Answer 7

^ correct... I gave the area of a circle as the circumference (2*pi*r). Area is pi*r^2.