Question

Given the standard electrode potentials, calculate the emf of a cell when [Co^(+2)] = 0.0155M and [Ag^(+1)] = 1.50M

Co(s) + 2Ag^(+1)(aq) --> Co^(+2)(aq) + 2Ag(s)

Co^(+2)(aq) + 2e- --> Co(s) E= -0.277 V
Ag^(+1)(aq) + 1e- --> Ag(s) E= +0.799 V

Answer 1

use the nernst equation

Answer 2

thank you! :)