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f(x)=(x−4)/(5x+2). Find an equation for the tangent line to the graph of f at x=1. Tangent line: y =
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do you know how to find slope of tangent at x=1 ?
ya its 22/49
i should say thats the slope of the normal line
hmm..i assume thats correct. so you just need 1 point now to get equation of line. when x=1, y=.. ? (put x=1, here y=f(x)=(x−4)/(5x+2).)
the point will be (1,f(1)) = (1,(1−4)/(5(1)+2))
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u got -3/7
you have slope = 22/49 point = (1,-3/7) can u find equation of line ?
y=(22/49)x-(22/49)+(3/7)
y=(22/49)x-(22/49)-(3/7)
ya thts what i got
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wait why -3/7
ah ok i see what i did my bad
good :)
messed it up in my head sorry and thank you
welcome ^_^
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