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OpenStudy (anonymous):
Let f(x)=|3x| .
Compute the limit
lim
h→0 (f(0+h)-f(0))/(h)
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OpenStudy (anonymous):
f(x)=|3x|
f(x+h) = |3(x+h)|
f(0) = 0
f(0+h) = |3(0+h)|
f(0+h) = |3h|
can you find this limit now???
OpenStudy (anonymous):
no, it's still saying it's incorrect. Thank you though
OpenStudy (anonymous):
\[\frac{ f(0+h)-f(0) }{ h }\] this is the format they give me
OpenStudy (anonymous):
lim
h→0 (f(0+h)-f(0))/(h)
= lim
h→0 3h/h
= lim
h→0 3
= 3 ---> is your answer
OpenStudy (anonymous):
yes, that's what i entered and it's still saying it's incorrect
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OpenStudy (anonymous):
so check your question may be it is wrong
OpenStudy (anonymous):
nope, that's exactly as the question reads. i've been working on this for 45 minutes and can't get it.
OpenStudy (anonymous):
o o i got it
OpenStudy (anonymous):
as f(x)=|3x|
then f(0+h) = |3h|
now f(0+h) = -3h for 3h<0
and f(0+h) = 3h for 3h>0
OpenStudy (anonymous):
I finally got it! thank you for all your help!
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OpenStudy (anonymous):
goooood
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