If f(x)=(x=8)^2, use the difference quotient to find Ax+Bh+C. A=2 B=1 C=?
Hi, re-write the f(x), (x=8)^2 means?
f(x)=(x+8)^2
sorry about that
expand followed the formula of (a +b)^2 = a^2 +2ab +b^2. your a is x, your b is 8. then you get .... Let me know the result. and then i guide you more
\[\frac{ f(x+h)-f(x) }{ h }= Ax+ Bh+ C\] A=2 B=1
that is the formula for limit, right?
I have C=1/16. what do you think?
oh, sorry, I make mistake, not that. a moment
okay, i've been working on this forever. no it's difference quotient. 1/16 is incorrect. I got zero but that's wrong as well
wait a moment , i nearly got it.
please, let check whether C =14
No, it must be C=16
\[f(x) = (x+8)^2 = x^2 +16x+64 \[f(x+h) = (x+h+8)^2 = x^2 +2xh +16x+h^2+16h+64\]
combine them into the your formula to get \[\frac{ 2xh+h^2+16h }{h}= 2x+h+16\]
you have A=2; B=1 and C=16. Hope this is right
that's correct. thanks a ton
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