Find the magnitude and direction angle of r=-48i+6j. I think I understand how to get the magnitude but not understanding the direction angle...
So to get the magnitude would be \[\sqrt{-48^{2}+6^{2}}\]
I think.
|dw:1360695998634:dw|
you are right on the magnitude
So the direction angle goes back to a unit circle?
Or am I just crazy
yeah it pretty much does, all the unit circle is is a way to look at angles, so take tan(x) = opp/ adj tan(x) = 6/48 <-- 48 is positive because it's just a magnitude the angle in the triangle is atan(6/48)
so the direction from positive x is 180 - that angle found
Okay then would the magnitude be kept in a fraction form 'cause the decimal goes on forever o.o
|dw:1360696335478:dw|
the magnitude is up to you or however your teacher wants it. it is safe to round off usually to 2 decimals
:) okay awesome that makes sense! Thanks a lot.
no problem, glad to help
Join our real-time social learning platform and learn together with your friends!