Write the equation of the line that is parallel to the line y = 2x + 2 and passes through the point (5, 3).
2x-y=7
Parallel lines must have the same gradient. The gradient of a line is m in the equation y=mx+c. So the gradient must be 2. Now by using the general formula for lines y-y1=M(x-x1) you can put in the coordinates (5.3) to get , y-3=2(x-5) which is the same as y=2x-7.
So it's y = 2x - 7.
Hey, thank you! Would you mind answering a few more?
Sure :)
Write the equation of the line that is perpendicular to the line y = 2x + 2 and passes through the point (6, 3). Write the equation of the line that is parallel to the line 3x − y = −3 and passes through the point (4, −2).
Perpendicular lines have the negative reciprical of the original line. So you basically take the orginal gradient and put it under 1. So the perpendicular gradient to 2 would be -1/2. Then just put that into the general formula. y-y1=M(x-x1) where y1 is 3 and x1 is 6.
For the next one, get the formula to look like y=mx+c. So y=3x+3. Then use the gradient of 3 and put it into the formula.
And, I also have Write the equation of the line that is perpendicular to the line 2x − 3y = 3 and passes through the point (−8, 2). Explain, in complete sentences, the relationship between the equations of perpendicular lines.
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