Choose the slope-intercept equation of the line that passes through the point shown and is perpendicular to the line shown. y = x - 8 y = -3x + 12 y = 3x - 24 y = -x - 4
So y-y1 = m(x-x1) where m is the gradient of the line and (x1,y1) is your known point on the line, being as your line is perpendicular to the line shown, you need to find the gradient of the line shown. Then find the reciprocal of that gradient. This gives you the gradient of the line you need to find, then you can use the point shown and your newly worked out gradient to work out the equation of the line
gradient of the line shown = 6/2 = 3 the reciprocal of 3 is 1/3 so to work out the equation of your line input m = 1/3 in to the equation above then, re-arrange.
Ok, so the slope is 1/3 for the line right? O:
yup the gradient or slope = 1/3 for the line you're trying to find
Then I would just need to find the y-axis...right?
Well, as I said above, you can use the equation y-y1 = m(x-x1) to find the equation of a line. So, for yours it would be y+6 = 1/3(x-6) If you re-arrange that, you'll get your equation
(x1,y1) is your point on the line you're given
Ok then D would be the answer, correct? ;D y = 1/3x - 4
One sec just checking
I got 1/3x - 8 y+6 = 1/3x - 2 y = 1/3x -2 -6 y= 1/3x -8
Oh, ok I just did one little calculation wrong ;D Thanks so much! C:
No Problem
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