Question

x^+3x-10=0

Answer 1

You need to get that in the form (x+a)(x+b). a and b need to multiply together to get -10 and add together to get 3. What 2 numbers do that?

Answer 2

One of them is negative and one is positive. The positive one needs to be bigger to give +3x.

Answer 3

Think about the factors of -10. You can have,
1 and -10
2 and -5
-1 and 10
-2 and 5.
Which of those add together to make 3.

Answer 4

I have -2 and +5 to factorise but dont equate unless I invert their values

Answer 5

so you have (x-2)(x+5)=0?

Answer 6

Yes

Answer 7

If you expand that you get x^2 + 3x - 10 = 0 so that is the right equation.

Answer 8

After that you need to find what x is.

Answer 9

Yes - but when I substitute -2 tpo do a checksum it looks wrong

Answer 10

Yes, that's because x doesn't = -2.

Answer 11

so , -2*-2+3*-2-10=0? no I get -12

Answer 12

Oh? - This may help me?

Answer 13

In the equation (x-2)(x+5) = 0, one of the two fractions must be 0.
So either x-2=0 or x+5=0. Therefore x=2 or 5

Answer 14

*-5 sorry.

Answer 15

That's why the inverses of -2 and 5 work.

Answer 16

Ah! I see simplifying it x must = -5 or 2. You are an absolute diamond!!!