Someone help me please ! (PICTURE BELOW)
@phi @satellite73 @Hero
rewrite the equation in the form \(4py=x^2\). the focus is at \((0,p)\) and the directrix is \(y=-p\)
I did that. I'm still stuck on my answer. I'm a little confused.
\[y=\frac{1}{12}x^2\] if you multiply both sides by 12, what would you get?
Meaning 12x12
\[12(y)=12(\frac{1}{12})x^2\\12y = x^2 \]
compare \(12y=x^2\) and \(4py=x^2\), what can you conclude?
Alright so wht would my answer be ?
compare the coefficients of \(y\). what is the value of \(p\)?
i got b am i right
that's not correct, dear. \[12 = 4p\\3=p\] now, the focus is at \((0,p)\) and the directrix is \(y=-p\) sub the value of p and you'll have the correct answer.
a ?
hello @sirm3d
focus at \((0,p)\) where \(p=3\) the focus would have the coordinates \((0,3)\)
I want to check my answer. Is it c @satellite73
the focus is \((0,3)\) because this is in the form \[12y=x^2\] so \(4p=12\implies p=3\)
therefore since the vertex is \((0,0)\) the directrix is 3 units down, namely at \(y=-3\)
as usual, it is C
Yes correct. I went over all this with the guy about but i'm now im over my answer. And i want to your right or wrong for my answer and i got c ?
Thank you @satellite73
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