Question

How did I get this wrong?
http://prntscr.com/sjlgj

Answer 1

Just curious. It marked it wrong but I'm sure I got it right.

Look:

x^2
----
x^6

=

1
----
x^-4

Now to make it positive we put it in the numerator

x^4
----
1

Which is just equal to

x^4

Answer 2

\[\large \frac{x^2}{x^6} \qquad = \qquad x^{2-6} \qquad = \qquad x^{-4}\]Do you see the mistake you made?
You had the correct power, but when you divide, you should be left with your X in the numerator, not the bottom one.

Answer 3

I don't think so.

\[\frac{ x^2 }{ x^6 } \rightarrow \frac{ 1 }{ x^6 - x^2 } \rightarrow \frac{ 1 }{ x^-4 } \rightarrow \frac{ x^4 }{ 1 }\rightarrow x^4\]

We subtract the denominator from the numerator.

Answer 4

\[\large \dfrac{x^a}{x^b} = x^{a - b} = \dfrac{1}{x^{b - a}}\]

Answer 5

You could write it like this if you wanted.\[\large \frac{x^2}{x^6} \qquad = \qquad \frac{1}{x^6x^{-2}} \qquad =\qquad \frac{1}{x^{6-2}} \qquad =\qquad \frac{1}{x^4} \qquad = \qquad x^{-4}\]

Answer 6

Zepdrix is right, you know.

Answer 7

You have the right idea (although the notation is a bit sloppy). You just made a tiny mistake, when you subtracted 2 from 6, it should give you `positive` 4.

Answer 8

If that's true, it should be -4,

\[\frac{ 1 }{ x^4 }\] would be fine.

Answer 9

Yes that would be a fine answer! :)

Answer 10

Yeah. Most people hate negative exponents, so it's good enough.

Answer 11

But if...

\[\frac{ x^6 }{ x^5 } = 6 - 5\]

Why would

\[\frac{ x^5 }{ x^6} = 6 - 5, too?\]

Answer 12

No, look at my 'formula' above here.

Answer 13

\[\large \frac{x^5}{x^6}=x^{5-6}\]
Yah your numbers are a little backwards on the second example. :) You always subtract the BOTTOM number, it doesn't matter which number is smaller. Always subtract the power in the denominator.

Answer 14

lololol good ole morgan freeman XDDD