Integral question: Please!! the Integral of
1/sqrt(2x-x^2) dx

Question

Integral question: Please!! the Integral of
1/sqrt(2x-x^2)  dx

jotopia34 · Answer

$$\int\limits1/({2x-x^2)}$$

pooja195 · Answer

∫ 1 / sqrt(2x-x^2) dx

Let's complete the square.

∫ 1 / sqrt(-(x^2-2x+1) + 1) dx
∫ 1 / sqrt(1 - (x-1)^2) dx

Let,

u = x-1
du = dx

∫ 1 / sqrt(1 - u^2) du
arcsin(u) + C
arcsin(x-1) + C

jotopia34 · Answer

pellet, i did sorry

jotopia34 · Answer

okay, complete the square it is. Only I don't remember how...:( please help pooja

pooja195 · Answer

This is the original problem.	4x2 – 2x – 5 = 0
Move the loose number over to the other side.	4x2 – 2x = 5
Divide through by whatever is multiplied on the squared term.
Take half of the coefficient (don't forget the sign!) of the x-term, and square it. Add this square to both sides of the equation.

Convert the left-hand side to squared form, and simplify the right-hand side. (This is where you use that sign that you kept track of earlier. You plug it into the middle of the parenthetical part.)


Square-root both sides, remembering the "±" on the right-hand side.  Simplify as necessary.	
Solve for "x =".	
Remember that the "±" means that you have two values for x.

pooja195 · Answer

ps just an example

jotopia34 · Answer

Ok, i see what you are saying, just had to refresh the memory. Thx again