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Mathematics 22 Online
OpenStudy (anonymous):

(3/x)+[13/(x-11)]

OpenStudy (anonymous):

I got -28 for the answer but didn't know if it was right

OpenStudy (tkhunny):

?? Is there a value for x?

OpenStudy (anonymous):

no just to simplify.

OpenStudy (anonymous):

its 3 over x + 13 over x-11 and I am just supposed to simplify.

OpenStudy (anonymous):

given \[\frac{ 3 }{ x } + \frac{13}{x-11}\] we can multiply any term by 1, right? We want a common denominator, so try multiplying each term by a version of 1... \[\frac{x-11}{x-11}\] and \[\frac{x}{x}\] respectively to see what happens.

OpenStudy (anonymous):

I did that and after everything i got -28

OpenStudy (anonymous):

If you don't have a value for x your answer should still include x. When you multiplied (x-11)/(x-11) and x/x what did you end up with?

OpenStudy (anonymous):

3x-33 over x^2-11x + 13x over x^2-11x

OpenStudy (anonymous):

would that be it or could i simplify more.

OpenStudy (anonymous):

Perfect. Now that you have a common denominator, you can combine your two fractions into one, combining like terms in your numerator: [(3x-33)+13x]/(x^2-11x)

OpenStudy (anonymous):

oh okay, so in the end it would be 16x-33 over x^2-11x?

OpenStudy (anonymous):

exactly! That's as simple as you can get. :) Good work

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