Water's heat of fusion is 80 cal/g. Its specific heat is 1.0 cal/g degrees celsius, and its heat of vaporization is 540 cal/g.
A canister is filled with 330g of ice and 100g of liquid water, both at 0 degrees celsius. The canister is placed in an oven until all the water has boiled off and the canister is empty. How much energy in calories was absorbed?

Question

Water's heat of fusion is 80 cal/g. Its specific heat is 1.0 cal/g degrees celsius, and its heat of vaporization is 540 cal/g.
A canister is filled with 330g of ice and 100g  of liquid water, both at 0 degrees celsius. The canister is placed in an oven until all the  water has boiled off and the canister is empty. How much energy in calories was absorbed?

anonymous · Answer

First find what is the heat absorbed by the ice to get converted into water
thats Q1(using the data of heat of fusion)

then the ice would have melted, and you would have water at 0 deg C.. so total water is 330g + 100 g = 440g (ofcourse  i know both get heated together, but its easier if you solve it this way).. Now find how much heat is required to raise it to 100 deg C (using the data of specific heat).. thats Q2

Finally find amount of heat required to boil that much of water at 100 deg C.. using (heat of vaporization data) thats Q3

Final answer would be sum .. Q1 + Q2 + Q3