Question

On the Apollo 14 mission to the moon, astronaut Alan Shepard hit a golf ball with a 6 iron. The acceleration due to gravity on the moon is 1/6 of its value on earth. Suppose he hits the ball with a speed of 27m/s at an angle 50 above the horizontal.
a) How much farther did the ball travel on the moon than it would have on earth?
b) For how much more time was the ball in flight?

Answer 1

take t=3.5s,
the velocity of x=dx/dt=3/2t^2-4t=4.375
velocity of y=dy/dt=t-2=1.5
the net velocity is obvious then
speed=sqrt(Vx^2+Vy^2)=sqrt(4.375^2-1.5^2)=4.11
perhaps there's some mistake, check it. Anyway you should have understood

Answer 2

got it ?

Answer 3

It's wrong, it says the answer should be in two significant figures

Answer 4

it could be some calculative problem
you can sort it out

Answer 5

I got 5.875 still wrong thanks for trying

Answer 6

4.625?

Answer 7

21.39

Answer 8

no it has to be two significant figures fore example: 45 , 67 not just one significant figure like 4 or 5

Answer 9

got it1369/64

Answer 10

still wrong

Answer 11

sorry,wait a minute

Answer 12

I only got when t =0 the answer is 2 , but I don't know how to get t = 3.5 !!

Answer 13

you don't use calculous?

Answer 14

first derivative，than The Pythagorean theorem. that cannot be wrong

Answer 15

I know that that's how I got when t =0 , I did the same exact way when t = 3.5 and I got 5.375 but wrong

Answer 16

do you know the answer?

Answer 17

my answer is 21.390625. I'm closely sure that it's correct

Answer 18

\[x= (1/2t^{3} - 2t^{2})........ y= (1/2t^{2}-2t)....\]

i just want to see the equations in a better format :D

Answer 19

\[dx/dt= (-3/2t^{4} - 4t^{2}) ...... dy/dt = (-1/t^{3} - 2)\]

Answer 20

now put t = 3.5

Answer 21

that's wrong

Answer 22

what ?? whats wrong in that?

Answer 23

U should get the derivative not the integration of the equation

Answer 24

omg.. !! please.. you need to work more on your math :-/