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OpenStudy (anonymous):
Prove:
Δ/s-a = s*tan a/2
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OpenStudy (anonymous):
\[\frac{ Δ }{ s-a } = s \tan \frac{ \alpha }{ 2 }\]
OpenStudy (anonymous):
using R.H.S ??
OpenStudy (anonymous):
\[\tan \frac{ \alpha }{ 2 } = \sqrt{\frac{ (s-b)(s-c) }{ s(s-a) }}\]
OpenStudy (anonymous):
and \[\Delta = \sqrt{s(s-a)(s-b)(s-c)}\]
hartnn (hartnn):
then its direct.
\(\dfrac{\Delta}{s-a} =\dfrac{ \sqrt{s(s-a)(s-b)(s-c)}}{s-a}=\dfrac{ \sqrt{s(s-b)(s-c)}}{\sqrt{s-a}}\)
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hartnn (hartnn):
\(s\tan \frac{ \alpha }{ 2 } =s \sqrt{\frac{ (s-b)(s-c) }{ s(s-a) }}= \sqrt{\frac{s (s-b)(s-c) }{ (s-a) }}\)
hartnn (hartnn):
LHS = RHS.
OpenStudy (anonymous):
we have to prove it using a single side
hartnn (hartnn):
okk.
OpenStudy (anonymous):
i think we should choose R.H.S
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hartnn (hartnn):
any1 can be chosen.,
\(\dfrac{\Delta}{s-a} =\dfrac{ \sqrt{s(s-a)(s-b)(s-c)}}{s-a}\\ =\dfrac{ \sqrt{s(s-b)(s-c)}}{\sqrt{s-a}} \\=\sqrt{\frac{s (s-b)(s-c) }{ (s-a) }} \\ =s \sqrt{\frac{ (s-b)(s-c) }{ s(s-a) }} \\ = s\tan \frac{ \alpha }{ 2 } \)
OpenStudy (anonymous):
WHAT HAPPENED IN THE SECOND STEP WITH s-a ???
hartnn (hartnn):
\(\dfrac{\sqrt{s-a}}{s-a}=\dfrac{1}{\sqrt{s-a}}\)
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