Question

A rectangular pasture has a fence around the perimeter. The length of the fence is 16x7 and the width is 48x4. What is the area of the pasture? (1 point)
a) 3x^3
b)128x^11
c)768x^11
d)768x^28

I KNOW the answer is c, but i need it explained. I already found it here once but can ANYONE explain how to do this?

Answer 1

Area of rectangular (here pasture) = Length * Width

Answer 2

Allright, so how do i do it? 16 * ^7 gives nothing and im so confused

How do i do 16x^7 * 48x^4?
I dont get this problem

Answer 3

Same thing with this > Simplify. 5^–1(3^–2)
If i type this into a calculator i get a stupid number

Answer 4

ok, treat constants and variables separately.
\(16x^7 \times 48x^4 = (16\times 48) \times(x^7 \times x^4)\)
got this ?

Answer 5

Okay... yes i think i get that... but where did the two Z come from

Answer 6

Z ?? there are no Z's there....

Answer 7

Whoops, sorry, okay, go on. I understand now

Answer 8

I think i get it

16 * 48 = 768

And 7 + 4 = 11?

Answer 9

good!

Answer 10

Okay, 1 more?

Answer 11

actually, its \(x^7 \times x^4 = x^{7+4}=x^{11}\)
and sure :)

Answer 12

Okay
something like this
Simplify (4xy2)3(xy)5
and (sorry) this
Evaluate a–4b2 for a = –2 and b = 4

Answer 13

Simplify (4xy^2)^3(xy)^5
Sorry

Answer 14

i believe the first one looks like this :
\((4xy^2)^3(xy)^5\)

Answer 15

ok, so you need to remember/understand few thing before u start:
\(\huge (ab)^n = a^nb^n\)
and
\(\huge (a^m)^n=a^{mn}\)

Answer 16

okay

Answer 17

The other problem i can't figure out how to write an equation

Answer 18

\(\large Evaluate \: \: a^{–4}b^2 \:\: for\:\: a = –2 \:\:and\:\: b = 4\)
right ?

Answer 19

Here you go

Answer 20

ok, for the previous one :
using, \(\huge (ab)^n = a^nb^n\)

\(\large (4xy^2)^3= 4^3 x^3 (y^2)^3\)
got this ?

Answer 21

Oh man. So confused

Answer 22

Are you doing Simplify (4xy^2)^3(xy)^5 ?

Answer 23

yes.

Answer 24

And you changed that to (4xy^2)^3=4^3x^3(y^2)^3....

Answer 25

How did you do that... that hurts my brain