I need help finding the exact value of cos^2pi/8-sin^2pi/8
use the identity, $$\cos (2x)=\cos^2(x)-\sin^2(x)$$
Simplify the following: (cos(pi))^2/8-sin(pi)^2/8 Evaluate cos(pi)^2. cos(pi)^2 = 1: 1/8-sin(pi)^2/8 Evaluate sin(pi)^2. sin(pi)^2 = 0: 1/8-0/8 Any number times zero is zero. 0/8 = 0: 1/8 Look for the additive identity. 1/8+0 = 1/8: Answer: 1/8
Sorry I wrote the problem wrong its actually cos^2(pi/8)-sin^2(pi/8)
Still you can use the above identity to find the answer
Can you give me the first step please I'm still lost
okaii so these are the steps for the problem: cos^2pi/8-sin^2pi/8 you can you the same methods and steps(similar) to do the other one you want to do? any questions or doubts you still have please post them :)
@some_someone jinxed401 is mentioning about $$\cos^2(\pi/8)-\sin^2(\pi/8)$$ not $$\frac{\cos^2(\pi)}{8}-\frac{\sin^2(\pi)}{8}$$ @jinxed401 As i said, consider the identity, $$\cos(2x)=\cos^2(x)-\sin^2(x)$$ if you substitute x=pi/8 what would the above equation be?
\[\cos(2\times \pi/8 ) =\cos^2(\pi/8)-\sin^2(\pi/8)\] I"m still not sure where to go here
the finally it can be cos(2pi/8) = cos(pi/4) = cos45 degrees = ... ?
45 degrees was the special angle in trigono.. u have to memorize the values of sin, cos, tan for the special angles
cos45 is \[(\sqrt{2}/2)\]
yes, that;s right
but I'm not seeing where you got 45 degrees from though because (pi/8) is does not come out to be (pi/4)
2/8 = 1/4 and 1 pi radian = 180 degrees so, 1/4 pi = 1/4 * 180 degrees = 45 degrees
it just converting unit radian to degree
Yes but where are you getting (1pi/8)
hoho... ur original problem is cos^2pi/8-sin^2pi/8 so, we change this by identity what our friend said above ^ thus, cos^2pi/8-sin^2pi/8 = cos(2pi/4) just doing for right side, dont look for left side because it has passed away :)
you are an amazing person
i just continue it :)
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