Question

Find values of x for
(logx)(logx^2) + logx^3 - 5 = 0
Halp please(medal for best answer)

Answer 1

\((logx)(logx^2) + logx^3 - 5 = 0\)
Remember that log(x^y) = y*log(x), then we have
(logx)(2logx) + 3logx - 5 = 0
Now you should be able to reduce this equation into a quadratic one.

Answer 2

sorry but i never done surds in brackets which is multiplication. well i dont think i have...

Answer 3

@tyteen4a03 help please

Answer 4

Surds in brackets? How did you get there?

Answer 5

(logx)(2logx) + 3logx - 5 = 0
These brackets?

Answer 6

i mean logs in brackets :P

Answer 7

@tyteen4a03 HELP PLEASE :(

Answer 8

i completely have no idea what to do...
Help please

Answer 9

logx * logx = log^2(x).