plz help.

a cyclist and a jogger set out at 10 a.m. from the same point, headed in the same direction. The average speed of the cyclist is twice the average speed of the jogger. In 1 h, the cyclist is 7 mi ahead of the jogger. Find the rate of the cyclist.

Question

plz help.


a cyclist and a jogger set out at 10 a.m. from the same point, headed in the same direction. The average speed of the cyclist is twice the average speed of the jogger. In 1 h, the cyclist is 7 mi ahead of the jogger. Find the rate of the cyclist.

anonymous · Answer

@ishrush

anonymous · Answer

$$\text{speed of cyclist} = 14~mph$$

anonymous · Answer

sweet thank you ..

anonymous · Answer

if we know that the speed of the cyclist is twice that of the jogger then if the cyclist is 7 miles away from the jogger, he is double the distance which is 14, and we are given time 1 hour which is the time in which we measure speed so he is going 14 miles per hour....as far as my understanding goes :)

anonymous · Answer

thanks that 
really helped me.:]

anonymous · Answer

anytime :)