Question

solve by any method
4x^2+36X=88

Answer 1

First thing I would do is divide everything by 4.

Answer 2

I Know that you get 4(x^2+36x-22)=0 this is the step were that factoring comes in and im geting confused

Answer 3

let it equal zero then take a common factor or 4

\[4(x^2 + 9x - 22) = 0\]

find the factors of -22 that add to 9

then the solution is

4(x + factor 1)(x + factor 2) = 0

then solve

x + factor 1 = 0

x + factor 2 = 0

to get the solutions.

Answer 4

I said divide, not factor. Get rid of it. 4 is not ever zero. You're done with it.

Answer 5

what i come up with is X=2 and x = -11

Answer 6

but the 36x is still there and it is devisable by 9

Answer 7

well campbell if you add 2 to -11 you come up with -9

Answer 8

\[4x^2+36x=88\]subtract the \(88\) and set the equation equal to \(0\):\[4x^2+36x-88=0\]factor out the \(4\):\[4(x^2+9x-22)=0\]the trinomial \(x^2+9x-22\) can be factored out to be:\[4[(x-11)(x+2)]=0\]now set each of the factors equal to \(0\):\[4=0\]\[x-11=0\]\[x+2=0\]and solve for each:\[4\neq0\]\[x=11\]\[x=-2\] tada! :)

Answer 9

hope that helps! @vortish :)

Answer 10

what about 11 + -2 = 9

so you are looking at

4(x - 2)(x + 11) = 0

now solve

x - 2 = 0

and

x + 11 = 0

for you solutions.