Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

Factor 5x4 - 30x2 - 135. 5(x2+ 9)(x2- 3) *********** 5(x - 3)(x + 3)(x2- 3) I think it is the one with ******* 5(x - 3)(x + 3)(x2+ 3)

OpenStudy (anonymous):

no sorry,its the last one \(5(x - 3)(x + 3)(x^2+ 3)\)

Parth (parthkohli):

\[5(x^4 - 6x^2 - 27) = 5(x^4 - 9x^2 + 3x^2 - 27)\]

Parth (parthkohli):

I think you can group the terms and factor.

OpenStudy (anonymous):

so it is the last one

OpenStudy (campbell_st):

this is an equation reducible to a quadratic take 5 as the common factor and then you have \[5(x^4 - 6x^2 - 27)\] which can be treated as \[5((x^2)^2 - 6(x^2) - 27)\]

OpenStudy (anonymous):

yes @Shannon20150

OpenStudy (anonymous):

will u help me again all of u

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!