Question

A stone is thrown horizontally at 20 m/s from the top of a cliff 63 m high. How fast is it moving the instant before it hits the ground?
a. 33 m/s
b. 40 m/s
c. 38 m/s
d. 29 m/s

Answer 1

Help please

Answer 2

They said use A^2+B^2???

Answer 3

You know that Ek = Ep:
mv^2 / 2 = mgh

Now solve for the vertical velocity v. g is the gravitational constant 9.8 and h is the height in meters

Answer 4

let A = v (the vertical velocity you get) and B = 20 (horizontal velocity)
Then the total velocity is:
\[\sqrt{A^{2}+B^{2}}\]