Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (angelwings996):

How many milliliters of the 0.5% solution must be added to the 2% solution to get a 0.65% solution?

OpenStudy (angelwings996):

Use the rational function: \[y = \frac{ (100)(0.02) + x(0.005) }{ 100 + x }\]

OpenStudy (anonymous):

This makes my head hurt XD

OpenStudy (anonymous):

This problem is very common in homeworks. Most of the time volume or mass is used as the parameter of interest, in this case it is volume. What you want to do is, in this case, assume you have 100mL of 2% solution, and you want to add just enough 0.5% solution to it so that the new solution is a 0.65% solution. In your case, y = 0.65, and x would be the amount of 0.5% solution you would add to make your solution 0.65%.

OpenStudy (angelwings996):

Okay, well how exactly would I start ? I know that my y = the function above and y2 would equal 0.0065 correct? It tells me I need to graph it to find x (which would be where they intersect) but everytime I do, there is no intersection

OpenStudy (angelwings996):

@Aeronautix

OpenStudy (anonymous):

How many mL of 0.5% solution are you starting out with?

OpenStudy (angelwings996):

I don't know

OpenStudy (anonymous):

Same

OpenStudy (angelwings996):

There is an example of how to do this problem in my textbook and it says to use the rational function given and to graph the function and whatever y2 is and where ever the intersection is would be the answer. Thats how they did it

OpenStudy (anonymous):

You try a calc.??

OpenStudy (angelwings996):

Yes, I used a graphing calculator like they said and there is no point that I see where they intersect

OpenStudy (anonymous):

Oh I see. There are an infinite number of combinations of volume that will give you a 0.65% solution. You must know how much of one solution you start out with. Mmmm, are you sure they don't specify a starting volume? Ok, so I guess assume the starting volume of 0.5% solution is x_1 and the volume you need from the 2% solution is x_2. Replace y with 0.0065, the solution you want to make, and 100 with x_1, the starting volume of 0.5% solution (which we will call a variable for now).

OpenStudy (anonymous):

Oh I know what your doing now

OpenStudy (angelwings996):

The only information I know for this problem is what I posted

OpenStudy (anonymous):

That cant be right? Unless...hold on.

OpenStudy (angelwings996):

It tells me just to graph the rational function, which I posted above and y2 whch would be 0.65% but transforming that into a decimal, not a percentage, and where the two points meet is the answer

OpenStudy (anonymous):

The solution to this problem is a rewritten form of the equation you posted: http://www.wolframalpha.com/input/?i=0.0065%3D%28x*0.02%2By*0.005%29%2F%28x%2By%29 The volume of 0.5% solution you need (let's call this x) to add to the unknown volume of 2% solution you have (let's call this y) is a volume that will depend on the volume of 2% solution you start out with, which is a variable since we don't know how much we have to start with. So you would need, according to WolframAlpha, 9 times as much volume of 2% solution you start out with.

OpenStudy (anonymous):

I'm not sure what your textbook is referring to when it asks for an intersection. :\

OpenStudy (anonymous):

Sorry, with lack of book Aeronautix and i can only go so far with this.

OpenStudy (angelwings996):

I wish I knew how to show what I am seeing because I have an online textbook

jimthompson5910 (jim_thompson5910):

If you graph y1 = (100*0.02+0.005x)/(100+x) and y2 = 0.0065 you won't be able to see both lines using the standard window view

jimthompson5910 (jim_thompson5910):

so you'll have to change your window

OpenStudy (angelwings996):

How do you change the window?

jimthompson5910 (jim_thompson5910):

if you make xmin = 600 xmax = 1200 ymin = -0.006 ymax = 0.012 then you should have a better view of both lines (and the point of intersection)

jimthompson5910 (jim_thompson5910):

what kind of calculator do you have?

jimthompson5910 (jim_thompson5910):

if you're using a TI-83, then you would hit the "window" button next to the "y=" button at the top then make the proper changes

OpenStudy (angelwings996):

@Aeronautix I know how the answer for the problem, I just don't know how to show the work

OpenStudy (angelwings996):

I don't own a graphing calculator so I just use one that is online

jimthompson5910 (jim_thompson5910):

which one do you use online?

jimthompson5910 (jim_thompson5910):

click settings

jimthompson5910 (jim_thompson5910):

in there you'll be able to change your window

OpenStudy (angelwings996):

Okay, but there is also a place where you can check for intersection and since that is what I am looking for I clicked on it and it tells me that there is no intersection

OpenStudy (angelwings996):

I don't know if maybe I am putting in 0.65% in wrong or what. I put it as 0.0065, is that correct?

OpenStudy (anonymous):

Hmm, you should think of getting a graphing calculator, it's an essential tool for doing math. Here i guess is a graphical solution, by plotting the two equations (you'd see the two equations at the top): http://www.wolframalpha.com/input/?i=y%3D%28%28100%29%280.02%29%2Bx%280.005%29%29%2F%28100%2Bx%29%2C+y%3D0.0065 --> 900mL of 0.5% solution for 100mL of 2% solution.

OpenStudy (anonymous):

0.0065 is correct.

OpenStudy (angelwings996):

@Aeronautix Yes, that is what I needed because 900 mL is correct

jimthompson5910 (jim_thompson5910):

take a look at this screenshot and it should all work out

OpenStudy (angelwings996):

I'm not sure though how it came up for you when I put it in the same way :/

OpenStudy (anonymous):

Ok.

OpenStudy (angelwings996):

@jim_thompson5910 Maybe I somehow put it in wrong, but I do see the intersection on your half

jimthompson5910 (jim_thompson5910):

I don't like this calculator. The x-axis is all messed up and I don't know why, but it does figure out the correct intersection point

jimthompson5910 (jim_thompson5910):

Personally, I prefer geogebra because you have more control over it and can do a ton more with it

OpenStudy (angelwings996):

I was just looking for a graphing calculator online for this problem because I have one on my phone which works really well but for this type of problem it just wasn't working out so I had to find another one

OpenStudy (angelwings996):

@Aeronautix @jim_thompson5910 thank you for your help, It really helped a lot

OpenStudy (anonymous):

Your welcome! I prefer WolframAlpha for all my college needs.

jimthompson5910 (jim_thompson5910):

If you can, download geogebra because it's definitely a better graphing program Let me know if you need help with that

jimthompson5910 (jim_thompson5910):

Once you have geogebra, it's also easier to send graphs just as you see them

OpenStudy (angelwings996):

Okay thanks, I'll go and download it right now

jimthompson5910 (jim_thompson5910):

ok tell me when you get it and have it running then I'll post the graph I got

OpenStudy (angelwings996):

Okay, It is downloading right now

jimthompson5910 (jim_thompson5910):

alright great

OpenStudy (angelwings996):

Okay, its all ready

jimthompson5910 (jim_thompson5910):

ok here is the graph I got (see attached)

jimthompson5910 (jim_thompson5910):

the red curve is the graph of y = (100*0.02+0.005x)/(100+x) the blue line is the graph of y = 0.0065

OpenStudy (angelwings996):

I got it, thank you!

jimthompson5910 (jim_thompson5910):

you're welcome

jimthompson5910 (jim_thompson5910):

feel free to ask any questions you have about geogebra it should be pretty straight forward, but you never know when you might get stuck

OpenStudy (angelwings996):

Alright, thank you so much for your help!

jimthompson5910 (jim_thompson5910):

sure thing

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!