A popular size of scuba-diving tank holds the amount of compressed air that
would occupy 71.2 ft^3 at a normal surface pressure of 1 atm. Th e air in the tank
is at a pressure of about 2250 lb/in.^2, so the tank itself can have a volume much
less than 71.2 ft^3. How large does the tank need to be to hold 71.2 ft^3? (Hint: Use
Boyle’s Law: PV = k. Remember that 1 atm = 14.7 lb/in.^2.)

Question

A popular size of scuba-diving tank holds the amount of compressed air that
would occupy 71.2 ft^3 at a normal surface pressure of 1 atm. Th e air in the tank
is at a pressure of about 2250 lb/in.^2, so the tank itself can have a volume much
less than 71.2 ft^3. How large does the tank need to be to hold 71.2 ft^3? (Hint: Use
Boyle’s Law: PV = k. Remember that 1 atm = 14.7 lb/in.^2.)

dumbcow · Answer

$$P_1V_1 = P_2V_2$$
$$2250V=(14.7)(71.2)$$
$$V = \frac{14.7*71.2}{2250}$$

anonymous · Answer

so would the tank be 15.4 ft? im a little confused..

dumbcow · Answer

??
no the tank would be whatever (14.7*71.2)/2250 is

anonymous · Answer

wow nevermind i was thinking of a completely different scenario then what the question was asking lol my bad