A polygon has n sides. Two of its angles are right angles. Each of the remaining angles equal to 150 degrees. calculate n. Please help! =)
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jimthompson5910 (jim_thompson5910):
Two of its angles are right angles...so we have 2*90 = 180 degrees so far
jimthompson5910 (jim_thompson5910):
The remaining angles are 150 degrees
there are n-2 angles left since we used up 2 angles (above), so the remaining angles add up to
150(n-2)
jimthompson5910 (jim_thompson5910):
in total, all n angles add to
180 + 150(n-2)
jimthompson5910 (jim_thompson5910):
now, you can use the formula
S = 180(n-2)
to find the sum of the interior angles of any polygon with n sides
jimthompson5910 (jim_thompson5910):
so if all angles add to 180 + 150(n-2)
AND
they add to 180(n-2)
then
180(n-2) = 180 + 150(n-2)
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jimthompson5910 (jim_thompson5910):
solve for n
OpenStudy (anonymous):
the answer would be 8 right because i found this online: For a polygon of n sides, the sum of all angles is 180n – 360 degrees
We are given that two sides are 90 degrees and the remainder are 150 degrees
Therefore 180n – 360 = 150(n – 2) + 90 x 2 = 150n – 300 + 180
180n = 150n + 360 + 180 – 300
30n = 240
n = 8
Therefore it is an octagon with six angles 150 degrees and two right angles
jimthompson5910 (jim_thompson5910):
that is correct
jimthompson5910 (jim_thompson5910):
solving 180(n-2) = 180 + 150(n-2) for n gives you n = 8
OpenStudy (anonymous):
but i am not understanding that procedure =/
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jimthompson5910 (jim_thompson5910):
which one: mine or the thing you found online?
OpenStudy (anonymous):
both =/
jimthompson5910 (jim_thompson5910):
ok where are you stuck on mine?
OpenStudy (anonymous):
how did you get the answer 8
jimthompson5910 (jim_thompson5910):
do you know how to solve 180(n-2) = 180 + 150(n-2) for n?
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OpenStudy (anonymous):
nope =/
jimthompson5910 (jim_thompson5910):
ok first distribute
180(n-2) = 180 + 150(n-2)
180n-360 = 180 + 150n-300
what's next?
OpenStudy (anonymous):
where did the 300 come from =/
jimthompson5910 (jim_thompson5910):
150 times 2 = 300
jimthompson5910 (jim_thompson5910):
150 times -2 = -300
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OpenStudy (anonymous):
ohh
jimthompson5910 (jim_thompson5910):
so what's next?
OpenStudy (anonymous):
you would have to group the numbers =/
jimthompson5910 (jim_thompson5910):
180 - 300 = ???
OpenStudy (anonymous):
-120
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jimthompson5910 (jim_thompson5910):
so
180n-360 = 180 + 150n-300
turns into
180n-360 = 150n-120
jimthompson5910 (jim_thompson5910):
then what?
OpenStudy (anonymous):
dont you group them like:
180n-150n=-120+360
jimthompson5910 (jim_thompson5910):
very good
jimthompson5910 (jim_thompson5910):
basically you get the like terms to the same side
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jimthompson5910 (jim_thompson5910):
180n - 150n = ???
OpenStudy (anonymous):
30n
jimthompson5910 (jim_thompson5910):
good
jimthompson5910 (jim_thompson5910):
-120 + 360 = ?
OpenStudy (anonymous):
then the other answer is 240
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jimthompson5910 (jim_thompson5910):
so we can say
30n = 240
OpenStudy (anonymous):
then you divide 240 by 30
jimthompson5910 (jim_thompson5910):
which in english translates to
30 times some number equals 240
jimthompson5910 (jim_thompson5910):
perfect
OpenStudy (anonymous):
Thank you very much! Finally i understand!
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